15 个提高效率的 Python 编程技巧

x, y = 1, 2print(x, y)x, y = y, xprint(x, y)

sentence_list = ["my", "name", "is", "George"]sentence_string = " ".join(sentence_list)print(sentence_string)

sentence_string = "my name is George"sentence_string.split()print(sentence_string)

[0]*1000 # List of 1000 zeros [8.2]*1000 # List of 1000 8.2's

x = {'a': 1, 'b': 2}y = {'b': 3, 'c': 4}z = {**x, **y}

name = "George"name[::-1]

def get_a_string():  a = "George"  b = "is"  c = "cool"  return a, b, csentence = get_a_string()(a, b, c) = sentence

a = [1, 2, 3]b = [num*2 for num in a] # Create a new list by multiplying each element in a by 2

m = {'a': 1, 'b': 2, 'c': 3, 'd': 4} for key, value in m.items():  print('{0}: {1}'.format(key, value))

m = ['a', 'b', 'c', 'd']for index, value in enumerate(m):  print('{0}: {1}'.format(index, value))

a_list = list()a_dict = dict()a_map = map()a_set = set()

name = "  George "name_2 = "George///"name.strip() # prints "George"name_2.strip("/") # prints "George"

test = [1, 2, 3, 4, 2, 2, 3, 1, 4, 4, 4]print(max(set(test), key = test.count))

import sysx = 1print(sys.getsizeof(x))

from xml.etree.ElementTree import Elementdef dict_to_xml(tag, d):    '''    Turn a simple dict of key/value pairs into XML    '''    elem = Element(tag)    for key, val in d.items():        child = Element(key)        child.text = str(val)        elem.append(child)    return elem